Math, asked by aditibhopale330, 4 months ago


2. Find the HCF and LCM of the numbers given below. Verify that their product is
equal to the product of the given numbers.
1.46,51 ​

Answers

Answered by aasthaa47
0

Step-by-step explanation:

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Answered by suman5420
0

i. 32 = 2 x 16  = 2 x 2 x 8  = 2 x 2 x 2 x 4  = 2 x 2 x 2 x 2 x 2 x 1  37 = 37 x 1  ∴ HCF of 32 and 37 =1  LCM of 32 and 37 = 2 x 2 x 2 x 2 x 2 x 37  = 1184 HCF x LCM = 1 x 1184  = 1184  Product of the given numbers = 32 x 37  = 1184  ∴ HCF x LCM = Product of the given numbers. 

ii. 46 = 2 x 23 x 1  51 = 3 x 17 x 1  ∴ HCF of 46 and 51 = 1  LCM of 46 and 51 = 2 x 23 x 3 x 17  = 2346  HCF x LCM = 1 x 2346  = 2346 Product of the given numbers = 46 x 51  = 2346  ∴ HCF x LCM = Product of the given numbers

iii. 15 = 3 x 5  60 = 2 x 30  = 2 x 2 x 15  = 2 x 2 x 3 x 5  ∴ HCF of 15 and 60 = 3 x 5  = 15  LCM of 15 and 60 = 3 x 5 x 2 x 2  = 60  HCF x LCM = 15 x 60  = 900  Product of the given numbers = 15 x 60  = 900  ∴ HCF x LCM = Product of the given numbers.

iv. 18 = 2 x 9  = 2 x 3 x 3  63 = 3 x 21  = 3 x 3 x 7  ∴ HCF of 18 and 63 = 3 x 3 = 9  LCM of 18 and 63 = 3 x 3 x 2 x 7  = 126  HCF x LCM = 9 x 126  = 1134  Product of the given numbers = 18 x 63  = 1134  ∴ HCF x LCM = Product of the given numbers. 

v. 78 = 2 x 39  = 2 x 3 x 13 104  = 2 x 52  = 2 x 2 x 26  = 2 x 2 x 2 x 13  ∴ HCF of 78 and 104 = 2 x 13  = 26  LCM of 78 and 104 = 2 x 13 x 3 x 2 x 2  = 312  HCF x LCM = 26 x 312 = 8112  Product of the given numbers = 78 x 104  = 8112  ∴ HCF x LCM = Product of the given numbers.

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