Question

2.
Find three consecutive numbers such that if they are divided by 10, 17, and 26 respectively.
the sum of their quotients will be 10.
(Hint: Let the consecutive numbers = x,x+1, 2+2, then
x +1 +2
10 17 26
= 10)​

Answer 1

Let X, (X+1), (X+2) are 3consecutive numbers.

X/10 + (X+1)/17+ (x+2)/26 =10L.C.M = 4420(442(X) +260(X+1) +170(X+2))/4420=10(442x+260x+260+170x+340)=4420x10(442x+260x+170x+260+340)=44200872x + 600= 44200

872x= 43600

872x= 43600X= 43600/872

872x= 43600X= 43600/872X= 50

872x= 43600X= 43600/872X= 50Ist no. (X)=50

2nd no.(x+1)= 50+1= 51

3rd no.(x+2)=50+2=52

3rd no.(x+2)=50+2=52The 3 consecutive numbers are 50, 51, 52.

hope it helps ✌