find remainder when p(x) is divided by q(x)
p(x) = x^3-6x^3+11x-6 , q(x)=x+2
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Answer:
Remainder ,R(x) = -60
Step-by-step explanation:
P(x) = x³ - 6x² + 11x - 6
Q(x) = x + 2
x + 2 = 0
x = -2
P(-2) = (-2)³ - 6(-2)² + 11(-2) - 6
= -8 - 24 - 22 - 6
= -60
R(x) = -60
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