Math, asked by chikkyhoney, 1 month ago

2. for which value of 0°< theta< 90°, above equation is not defined?​

Answers

Answered by princessridhima022
0

Answer:

0°=90°

Step-by-step explanation:

Cosθ/(1 - sinθ) + cosθ/(1 + sinθ) = 4 (Given)

Simplifying,

= Cosθ(1 + sinθ) + cosθ(1 - sinθ) /(1 - sinθ)(1 + sinθ) = 4

= Cosθ + cosθ × sinθ + cosθ - cosθ.sinθ} / (1 - sin²θ) = 4

Since, sin²x + cos²x = 1 therefore, (1 - sin²θ) = cos²θ

= 2cosθ/cos²θ = 4

= 2/cosθ = 4

= cosθ = 1/2

= cos 60°

Thus, when 0 < θ < 90° , then θ = 60°

If the given equation is not defined, ie. (1 - sinθ) = 0

in 0 < θ < 90° , sinθ = 1 at 90°

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