Question

2 gram of Mg3N2 on complete hydrolysis give R liter volume of NH3 at NTP calculate value of R​

Answer 1

Answer:

Ammonium chloride undergoes decomposition as:

53.5g

1mol

NH

4

Cl(s)

→

1mol

1mol

NH

3

(g)

+HCl(g)

∵53.5gNH

4

Cl give 1 mol NH

3

∴26.25gNH

4

Cl will give

53.5

1

×26.25moleNH

3

=0.5mole

PV=nRT

1×V=0.5×0.0821×300

V=12.315litreample

Answer 2

Answer:

Explanation:

1 mole = 6.022 x 1023 molecules. So number of molecules of ammonia in 1 ml = 6.022 x 1023/22400. Now, multiply this number by 4 to get the total number of atoms as each molecule of ammonia has 4 atoms ( 1 N and 3 H)