Math, asked by swaransingh49957, 5 hours ago

Simplify combining like terms:-​

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Answered by aarenmishra
10

Step-by-step explanation:

Here you go,

1- When term have the same algebraic factors, they are like terms.

Then,

= (21b + 7b – 20b) – 32

= b (21 + 7 – 20) – 32

= b (28 – 20) – 32

= b (8) – 32

= 8b – 32

2- When term have the same algebraic factors, they are like terms.

Then,

= 7z3 + (-z2 + 13z2) + (-5z – 15z)

= 7z3 + z2 (-1 + 13) + z (-5 – 15)

= 7z3 + z2 (12) + z (-20)

= 7z3 + 12z2 – 20z

3- When term have the same algebraic factors, they are like terms.

Then,

= p – p + q – q – q + p

= p – q

4- When term have the same algebraic factors, they are like terms.

Then,

= 3a – 2b – ab – a + b – ab + 3ab + b – a

= 3a – a – a – 2b + b + b – ab – ab + 3ab

= a (1 – 1- 1) + b (-2 + 1 + 1) + ab (-1 -1 + 3)

= a (1 – 2) + b (-2 + 2) + ab (-2 + 3)

= a (1) + b (0) + ab (1)

= a + ab

5-When term have the same algebraic factors, they are like terms.

Then,

= 5x2y + 3yx2 – 5x2 + x2 – 3y2 – y2 – 3y2

= x2y (5 + 3) + x2 (- 5 + 1) + y2 (-3 – 1 -3) + 8xy2

= x2y (8) + x2 (-4) + y2 (-7) + 8xy2

= 8x2y – 4x2 – 7y2 + 8xy2

6- When term have the same algebraic factors, they are like terms.

Then,

= 3y2 + 5y – 4 – 8y + y2 + 4

= 3y2 + y2 + 5y – 8y – 4 + 4

= y2 (3 + 1) + y (5 – 8) + (-4 + 4)

= y2 (4) + y (-3) + (0)

= 4y2 – 3y

Hope it helps u

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Answered by XxFantoamDEADPOOLXx
9

(i)21b - 32 + 7b - 20b

=> 21b +7b - 20b - 32

=> 21b +7b - 20b - 32=> 28b - 20b - 32

=> 8b - 32

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(ii) -z² + 13z² - 5z +7z² - 15z

=>-z² + 13z² - 5z +7z² - 15z

=>19z²-5z-15z

=>19z²-20z

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(iii)p - (p - q) - q - (q - p)

=>p-(p-q)-q-(q-p)

=>p-p+q-q-q+p

=>q+p

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(iv) 3a - 2b - ab- (a−b + ab) + 3ab + b - a

=>3a - 2b - ab - a+b - ab + 3ab +b - a

=>(3a-2a)+(-2b +2b) + (-2ab + 3ab)

=>a + ab = (1+b)

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(v)In photo

In photo

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(vi)In photo

In photo

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