Question

2. If (–15) + x = 0, 10 + y = 0 and z + (–5) = 0, then the value of x2 ÷ (z –y) is :

(A) 25

(B) 15

(C) 5

(D) 10


please answer the correct answer

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Answer 1

Answer:

-15 + x = 0

or, x = 15

10 + y = 0

or, y = -10

z + (-5) = 0

or, z - 5 = 0

or, z = 5

By putting the values of x, y and z, we get

${x}^{2} \div (z - y)$

${(15)}^{2} \div (5 - ( - 10))$

$225 \div (5 + 10)$

$225 \div 15$

$= 15$

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Answer 2

Step-by-step explanation:

hello mate

her your answer

option is (B)