Question

α 2 iii. In the above situation, find the value of sinacos a/2- cosasin a/2​

Answer 1

Answer:

0

Step-by-step explanation:

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Question

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In triangle ABC, right-angled at B, if tanA=

3

1

, find the value of

(i) sinAcosC+cosAsinC

(ii) cosAcosC−sinAsinC

Medium

Solution

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Given that,

In △ABC,∠B=90

∘

and tanA=

3

1

=tan30

∘

⟹∠A=30

∘

Hence, ∠C=60

∘

(i)sinAcosC+cosAsinC=sin30

∘

cos60

∘

+cos30

∘

sin60

∘

=

2

1

×

2

1

+

2

3

×

2

3

=

4

1

+

4

3

=

4

4

=1

(ii)cosAcosC−sinAsinC=cos30

∘

cos60

∘

−sin30

∘

sin60

∘

=

2

3

×

2

1

−

2

1

×

2

3

=

4

3

−

4

3

=0

Answer 2

entte q ll reply tha.

×

2

1

+

2

3

×

2

3

=

4

1

+

4

3

=

4

4

=1

(ii)cosAcosC−sinAsinC=cos30

∘

cos60

∘

−sin30

∘

sin60

∘

=

2

3

×

2

1

−

2

1

×

2

3

=

4

3

−

4

3

=0