Question

2.
In AABC, if AB = BC = CA = 2 units, then the length of the median of AABC is
a) 13
13
b)
c) 2/3
d) 43
2​

Answer 1

Step-by-step explanation:

Here,

In a triangle ABC, AB = BC = CA = 2 units.

Let AD be a median of a triangle ABC.

Then,

All sides of triangle ABC are equal, so it is an equilateral triangle.

So, Area of triangle = √3 a²

4

= √3 × 2²

4

= √3

BD = CD = 1 unit

Since in equilateral triangle, median is perpendicular to the base.

Now, using Pythagoras theorem,

AD = √(AC) ²-(CD)²

= √2² - 1²

= √4-1

= √3 units