2. In the figure, if <ADC = <CBP then
prove that [] ABCD is cyclic.
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Answer:
we have given that
angle ADC= angle CBP
now, angle CBP+ angle CBA= 180° .... (linear angles)
therefore angle ADC + angle CBA = 180°
therefore, quadrilateral ABCD is cyclic
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it is easy to prove
it may be help you .
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