Question

2 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30∘ to 60∘ as he walks towards the building. Find the distance he walked towards the building.​

Answer 1

★Solution:-

• AB= 30-1.5=28.5 cm

• In ΔABD:−tan30∘=BDAB

• ⇒BD=(28.5)3

• In ΔABC:−tan60∘=BCAB

• ⇒BC=3(28.5)

• CD= BD-BC

• =28.5(3−31)

• =28.5(32)=32.91m

Hence , The Answer is 32.91.

Answer 2

Question:

1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30∘ to 60∘ as he walks towards the building. Find the distance he walked towards the building.

refer to the attachment

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