2 MA current flowing for 20 seconds. find charges
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ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec.
ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec. Charge flowing through a conductor in one second is given as charge=current×time. It is given that the current through the conductor is 1.6 mA, that is, 1.6×10
ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec. Charge flowing through a conductor in one second is given as charge=current×time. It is given that the current through the conductor is 1.6 mA, that is, 1.6×10 −3
ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec. Charge flowing through a conductor in one second is given as charge=current×time. It is given that the current through the conductor is 1.6 mA, that is, 1.6×10 −3 A
ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec. Charge flowing through a conductor in one second is given as charge=current×time. It is given that the current through the conductor is 1.6 mA, that is, 1.6×10 −3 ATherefore, charge =1.6×10
ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec. Charge flowing through a conductor in one second is given as charge=current×time. It is given that the current through the conductor is 1.6 mA, that is, 1.6×10 −3 ATherefore, charge =1.6×10 −3
ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec. Charge flowing through a conductor in one second is given as charge=current×time. It is given that the current through the conductor is 1.6 mA, that is, 1.6×10 −3 ATherefore, charge =1.6×10 −3 ×1=1.6×10
ANSWERA current of 1 ampere is said to flow when 1 coulomb of charge passes a given point in 1 sec. Charge flowing through a conductor in one second is given as charge=current×time. It is given that the current through the conductor is 1.6 mA, that is, 1.6×10 −3 ATherefore, charge =1.6×10 −3 ×1=1.6×10 −3
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