Question

2 moles of zinc reacts with a cupric chloride solution containing 6.023×10^22 formula units of CuCl2(aq) Calculate the moles of copper obtained. Zn(s) + CuCl2(aq) - ZnCl2(aq) + Cu(s)

Answer 1

Zn + CuCl2 → ZnCl2 + Cu
here we see 1 mole of Zn react with 1 mole of CuCl2 and forms 1 mole of Cu

a/c to question,
mole of Zn = 2
and 6.023 × 10²² formula unit of CuCl2
hence mole of CuCl2 = 6.023× 10²²/6.023× 10²³

= 0.1

mole of CuCl2 = 0.1

here limiting reagent is CuCl2 . becoz after disassociation of 0.1 mole of CuCl2 reaction will be stop . because no more CuCl2 ocurr for continuing reaction .

hence, 0.1 mole of zn react with 0.1 mole of CuCl2 and form 0.1mole of Cu

hence, mole of copper obtained = 0.1 mole

Answer 2

Answer:

answe

Explanation:

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