2 pieces of lens 2 into 3 by 5 metres and 3 into 3 by 10 are cut off from a rope level metres long what is the length of the remaining rope?
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Answer:below is the answer. If it is useful please mark me brainliest
Step-by-step explanation:Given
Total length of the rope =11 m
If the rope is cut into 3 pieces
Length of the first piece = 2 3/5=13/5 m
Length of the second piece =3 3/10=33/10 m
We have to find out length of the third piece =x
x= total length -(length of the first piece + length of the second piece)
=11 - (13/5+33/10)
=11-[(26+33)/10]
=11/1 - 59/10
=(110-59)/10
=51\10
=5 1/10 m
Therefore
Length of the remaining piece =x =5 1/10 m
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