Question

2. Please select the three right choices that are logically right:
A. Rohan is a magician.
B. All jesters are magicians.
C. Some jesters are criminals.
D. Some magicians are criminals.
E. Rohan is a jester.​

Answer 1

Answer:

Step-by-step explanation:

A B E

Jester is subset of magician and if someone is jester then he magician too.

Answer 2

Answer:

A,B,E are three right choices that are logically right.

Step-by-step explanation:

Given options are Rohan is a magician,All jesters are magicians,some jesters are criminals,Some magicians are criminals,Rohan is a jester.

Here according to option B,

All jesters are magicians

and according to option A,

Rohan is a magician

So,we can say Rohan is a jester.

And it is equal to option E.

Therefore, option A,B,E are correct options.

This is a problem of Mathematics.

Some important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more Mathematics problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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