Question

2 power x-2=3power y and ​

Answer 1

Answer:

(x , y) = ( -∞, -∞   )  ,   ( log3/4÷log2 ,  log3/16÷log3  )

Step-by-step explanation:

2^(x-2) = 3^y

4^x = 3^(y+1)

2^x = 4*3^y

2^2x = 16*3^2y = 3^(y+1)

3^y= 0 , 3/16  → y = -∞ , log3/16÷log3

then

2^(x-2) = 0 , 3/16

2^x = 0 , 3/4   → x =  -∞ , log3/4÷log2

(x , y) = ( -∞, -∞   )  ,   ( log3/4÷log2 ,  log3/16÷log3  )