2. Q. How many phenotypic, genotypic classes
will be expected in the F, populations of the
following crosses- AA bb CC dd x aa BB cc DD?
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Explanation:
two types
The plant having genotype AABbCC is heterozygous for only one character B. Number of "gametes = 2n", where n is the heterozygosity." Since n = 1 so 2 gametes will be formed. Those are ABC and AbC. So the two types of gametes will be ABC and AbC.
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