(2 root 5 - root 7)square
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sry it is wrong answer u applied wrong property
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(2√5-√7)²
using identity (a-b)²=a²-2ab+b²
(2√5)²-2×2√5×√7+(√7)²
4×5-4√35+7
20+7-4√35
27-4√35
using identity (a-b)²=a²-2ab+b²
(2√5)²-2×2√5×√7+(√7)²
4×5-4√35+7
20+7-4√35
27-4√35
how - 4 come
(a-b) ² = a²-2ab+b²
in the last step how +4come
check it again I changed it
oky
solv my nxt question s
??
2/5root7+2
Rationalize
2/5√7+2×5√7-2/5√7-2= 2(5√7-2)/(5√7)²-(2)²=10√7-4/25×7-4=10√7-4/175-4=10√7-4/171
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