Question

(2+root3) (2-root3) find the value of this question

Answer 1

Answer:

This is in the form

(a+b)(a-b) = a^2-b^2

${a}^{2} - {b}^{2} = {2}^{2} - { \sqrt{3} }^{2}$

= 4-3

= 1☑️☑️☑️

Answer 2

Answer:

$(2 + \sqrt{3} )(2 - \sqrt{3} ) \\ = {2}^{2} - { \sqrt{3} }^{2} \\ = 4 - 3 \\ \\ = 1$

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