Question

2. The population of a town increases by 20% every
year. If its present population is 2,16,000. Find its
population (i) after 2 years, (ii) 2 years ago.(want explanation by usin depreciation and appreciation formula)​

Answer 1

Step-by-step explanation:

Formula 1: Let P be the population of a city at the beginning of the certain year and the population grows at a constant rate R% per annum, then:

Populationafternyears=P(1+R100)n

Formula 2: Let P be the population of a city or a town at the beginning of a certain year. If the population grows at the rate of R1% during the first year and R2% during the second year, then:

Populationafter2years=P(1+R1100)×(1+R2100)

Formula 3: Let P be the population a city or a town at the beginning of a certain year. If the population decrease at the rate of R% per annum, then:

Populationafternyears=P(1−R100)n

Depreciation

It is a well-known fact that the constant use of any machine or any other article causes wear and tear due to which its value decreases with time. The relative decreases in the value of a machine over a period of time is its depreciation. Depreciation per unit of time gives the rate of depreciation. The value at any time is called the depreciated value.

Formula for Depreciation

First Formula: If V0 is the value of an article at a certain time and R% per annum is the rate of depreciation, then the value of Vn at the end of a year is:

Vn=V0(1−R100)n

Second Formula: If V0 is the value of an article at a certain time and the rate of depreciation is R1% for the first n1 years, R2% for next n2 years and so on and Rk% for the last nk years the value at the end of n1 + n2 +………..+ nk years is:

V=V0(1+R1100)n1×(1+R2100)n2……×(1+R2100)nk

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Answer 2

Step-by-step explanation:

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answer in attachment