Question

the area of the following figure is a)144cm2
b)168cm2
c)192cm2
d)236cm2
give me step by step explanation​

Answer 1

ANSWER.

• The area of the figure is 192 cm².

SOLUTION.

Refer to the attachment for the figure.

In ABCD,

→ AB = BC = CD = AD = 12 cm

So,

→ Area(ABCD) = 12 × 12 cm² = 144 cm²

Again,

ABCD is a square.

→ ∠ABC = 90°

→ ∠CBE = 90°

Therefore,

→ ∆CBE is a right angled triangle.

Similarly,

→ ∆ADF is a right angled triangle.

→ Area(∆CBD) = Area(∆ADF) = 1/2 × Base × Height.

Here,

→ Base = 4 cm.

→ Height = 12 cm.

Area of each triangle = 1/2 × 4 × 12 cm²

= 24 cm²

Total area of the figure,

= Area of square + Sum of areas of two triangles

= (144 + 24 + 24) cm²

= (144 + 48) cm²

= 192 cm²

★ Hence, Option C is the correct answer.

Answer 2

my answer is 192cm2 is the answer