2/x+2/3y=1/6 3/x+2/y=0 solve the following simultaneous equation
Answers
2/x + 2/3y = 1/6 --( 1 )
3/x + 2/y = 0 ---( 2 ) are two given
simultaneous equations ,
let 1/x = a , 1/y = b
2a + 2b/3 = 1/6
( 6a + 2b )/3 = 1/6
6a + 2b = 1/2
12a + 4b = 1 -----( 3 )
3a + 2b = 0 -----( 4 )
multiply equation ( 4 ) with 2 and subtract
from ( 3 ) , we get
6a = 4
a = 4/6
a = 2/3
put a value in equation ( 4 ) , we get
3( 2/3 ) + 2b = 0
2 + 2b = 0
2b = -2
b = -1
Therefore b,
a = 2/3 ,. b = -1
1/x = 2/3 , 1/y = -1
x = 3/2 , y = -1
I hope this helps you.
: )
Answer:
Step-by-step explanation:
Hi ,
2/x + 2/3y = 1/6 --( 1 )
3/x + 2/y = 0 ---( 2 ) are two given
simultaneous equations ,
let 1/x = a , 1/y = b
2a + 2b/3 = 1/6
( 6a + 2b )/3 = 1/6
6a + 2b = 1/2
12a + 4b = 1 -----( 3 )
3a + 2b = 0 -----( 4 )
multiply equation ( 4 ) with 2 and subtract
from ( 3 ) , we get
6a = 4
a = 4/6
a = 2/3
put a value in equation ( 4 ) , we get
3( 2/3 ) + 2b = 0
2 + 2b = 0
2b = -2
b = -1
Therefore b,
a = 2/3 ,. b = -1
1/x = 2/3 , 1/y = -1
x = 3/2 , y = -1
I hope this helps you.
: )
Your rating: Excellent!
5Hi ,
2/x + 2/3y = 1/6 --( 1 )
3/x + 2/y = 0 ---( 2 ) are two given
simultaneous equations ,
let 1/x = a , 1/y = b
2a + 2b/3 = 1/6
( 6a + 2b )/3 = 1/6
6a + 2b = 1/2
12a + 4b = 1 -----( 3 )
3a + 2b = 0 -----( 4 )
multiply equation ( 4 ) with 2 and subtract
from ( 3 ) , we get
6a = 4
a = 4/6
a = 2/3
put a value in equation ( 4 ) , we get
3( 2/3 ) + 2b = 0
2 + 2b = 0
2b = -2
b = -1
Therefore b,
a = 2/3 ,. b = -1
1/x = 2/3 , 1/y = -1
x = 3/2 , y = -1
I hope this helps you.