2/x+3/y=13; 5/x-4/y=-2 Solve the given simultaneous equation.
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Answer :
Given that,
2/x + 3/y = 13 ...(i)
5/x - 4/y = - 2 ...(ii)
Now, multiplying (i) by 5 and (ii) by 2, we get
10/x + 15/y = 65
10/x - 8/y = - 4
On subtraction, we get
23/y = 69
or, y = 1/3
Now, putting y = 1/3 in (i), we get
2/x + 3/(1/3) = 13
or, 2/x + 9 = 13
or, 2/x = 4
or, x = 1/2
Therefore, the required solution be
x = 1/2, y = 1/3
Hope it helps! (:
Given that,
2/x + 3/y = 13 ...(i)
5/x - 4/y = - 2 ...(ii)
Now, multiplying (i) by 5 and (ii) by 2, we get
10/x + 15/y = 65
10/x - 8/y = - 4
On subtraction, we get
23/y = 69
or, y = 1/3
Now, putting y = 1/3 in (i), we get
2/x + 3/(1/3) = 13
or, 2/x + 9 = 13
or, 2/x = 4
or, x = 1/2
Therefore, the required solution be
x = 1/2, y = 1/3
Hope it helps! (:
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