Question

4x+y=34 ; x+4y=16 By equating coefficients of variables, solve the equation.

Answer 1

(4x+y=34)*4 ...(i)
(x+4y=16)*1 ...(ii)

Subtrating (ii) from (i)
16x+4y=136
x+4y=16
(-) (-) (-)

15x = 120
x=8

Putting x=8 in (i)
4x+y=34
4*8+y=34
32+y=34
y=2

Therefore, x=8 & y=2
:) :)

Answer 2

Solution :

Given simultaneous equations

are

4x + y = 34 ---( 1 )

x + 4y = 16 ---( 2 )

Now , multiply equation ( 2 ),

With 4 , we get

4x + 16y = 64 --( 3 )

Subtract ( 1 ) from ( 3 ) ,we get

15y = 30

=> y = 30/15

y = 2

Substitute y = 2 in equation ( 2 ),

we get

x+ 4× 2 = 16

=> x = 16 - 8

=> x = 8

Therefore ,

x = 8 , y = 2

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