x-2y=-10; 3x-5y=-12 By equating coefficients of variables, solve the equation.
Answers
Answered by
78
x - 2y = - 10
=> 3x - 6y = - 30 -------(1)
3x - 5y = - 12 --------(2)
On subtracting equation 1 from 2, we get
-5y + 6y = - 12 + 30
=> y = 18
On substituting the value of y in equation (1), we get
x - 36 = - 10
=> x = 26
=> 3x - 6y = - 30 -------(1)
3x - 5y = - 12 --------(2)
On subtracting equation 1 from 2, we get
-5y + 6y = - 12 + 30
=> y = 18
On substituting the value of y in equation (1), we get
x - 36 = - 10
=> x = 26
Answered by
39
Given,
x - 2y = -10 × 3
3x - 5y = -12 × 1
--------------------
3x - 6y = -30
3x - 5y = -12
-------------------
y = 18
Substitute y in eq 1
x - 2 (18) = -10
x - 36 = -10
x = -10 + 36
x = 26
x - 2y = -10 × 3
3x - 5y = -12 × 1
--------------------
3x - 6y = -30
3x - 5y = -12
-------------------
y = 18
Substitute y in eq 1
x - 2 (18) = -10
x - 36 = -10
x = -10 + 36
x = 26
Similar questions