Question

x/3+y/4=4; x/2-y/4=1 Solve the given simultaneous equation.

Answer 1

$\textbf{Answer}$

Given equations are,
$\textbf{x/3 + y/4 = 4}$ ------(1)
$\textbf{x/2 - y/4 = 1}$ -------(2)

Since coefficients of y are equal and opposite,we can eliminate y to find the value of x.

$\textbf{Lets add equations (1) and (2),}$

=> (x/3 + y/4) + (x/2 - y/4) = 4 + 1

=> x/3 + x/2 + y/4 - y/4 = 5

=> (2x + 3x)/6 = 5

=> 5x = 5×6

=> x = 6

$\textbf{Lets put the value of x}$ in $\textbf{equation (1),}$

x/3 + y/4 = 4
=> 6/3 + y/4 = 4
=> 2 + y/4 = 4
=> y/4 = 2
=> y = 8


$\textbf{x = 6}$
$\textbf{y = 8}$


$\textbf{Hope My Answer Helped}$
$\textbf{Thanks}$

Answer 2

Step-by-step explanation:

I hope it help's you my brother