Question

2^x+4,-2^x+2=3 find x

Answer 1

$2 {}^{x + 4} - 2 {}^{x + 2} = 3$

$2 {}^{x} .2 {}^{4} - 2 {}^{x} .2 {}^{2} = 3$

$now \: take \: 2 {}^{x} common$

$2 {}^{x} (2 {}^{4} - 2 {}^{2} ) = 3$

$2 {}^{x} .12 = 3$

$2 {}^{x} .2 {}^{2} .3 = 3$

$2 {}^{x} .2 {}^{2} = 1$

Now bases are same so powers will be add.

$2 {}^{x + 2} = 1$

$2 {}^{x + 2} = 2 {}^{0}$

Now bases are same so compare powers.

$x + 2 = 0$

$x = - 2$

Thanks