Question

Three coins are tossed together. Find the probability of getting utmost 2 heads​

Answer 1

Total no. of outcomes are,

HHT , HTH , HTT , HHH

THT ,  TTH , TTT , THH

Favourable outcomes are,

HHT, HTH , HTT , THT , TTH , TTT , THH

Hence, P(at most 2 heads) = 7/8

Answer 2

Answer:$\frac{Number of Favourable Outcomes}{Total Number of Outcomes}$

Therefore,                     According to question :

Step-by-step explanation: 3 coins =HT,HT,HT

To Prove : Probability of getting 2 heads

PROBABILITY = $\frac{6}{2}$

                        =3