Question

(2 x minus y + z whole square) -( 2 x + y - z whole
square)​

Answer 1

Here is the answer you were looking for:

$\begin{gathered} {(2x - y + z)}^{2} \\ \\ using \: the \: identity \\ {(a - b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2bc + 2ca \\ \\ = {(2x)}^{2} + {(y)}^{2} + {(z)}^{2} - 2 \times 2x \times y - 2 \times y \times z + 2 \times z \times 2x \\ \\ = 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4xz\end{gathered}$