Question

A particle is moves along a circle with a constant speed of 10ms inverse from Ato B which are the ends of its diameter The change in velocity​

Answer 1

Change in velocity of a particle in circle in given by,

∣Δ

v

ˉ

∣=

v

1

2

+v

2

2

+2v

1

v

2

cos(π−θ)

Since [∣

v

1

ˉ

∣=∣

v

2

ˉ

∣]=v

∣Δ

v

ˉ

∣=2vsin

2

θ

On putting the values of vandθ

=(2×10)×sin(30

o

)

=10m/s

Hence the change in velocity is 10m/s

Answer 2

Answer:

Hiii di

Good morning

Have a great day ahead

I'm your junior

I'm Rimsha Aftab from

Class 9th

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