2/x square-32x+1/21. factorise
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Answer:
Step-by-step explanation:
To find the roots of the quadratic equation equate it to 0
Let f(x)=21 x^{2}-2 x+\frac{1}{21}=0f(x)=21x
2
−2x+
21
1
=0
On taking LCM, we get,
441 x^{2}-42 x+1=0441x
2
−42x+1=0
The above in equation is in (a-b)^{2} = 0(a−b)
2
=0 form
Where, a = 21x; b = 1
On using, the above formula, we get,
(21 x-1)^{2}=0(21x−1)
2
=0
On solving, we get,
21 x-1=0; \ \ 21 x-1=021x−1=0; 21x−1=0
\Rightarrow 21 x=1; \ \ 21 x=1⇒21x=1; 21x=1
Thus, the value of x are,
x=\frac{1}{21}, \frac{1}{21}x=
21
1
,
21
1
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