Math, asked by prisha9307, 2 months ago

2/x square-32x+1/21. factorise


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Answers

Answered by manjulamaram1982
2

Answer:

Step-by-step explanation:

To find the roots of the quadratic equation equate it to 0

Let f(x)=21 x^{2}-2 x+\frac{1}{21}=0f(x)=21x

2

−2x+

21

1

=0

On taking LCM, we get,

441 x^{2}-42 x+1=0441x

2

−42x+1=0

The above in equation is in (a-b)^{2} = 0(a−b)

2

=0 form

Where, a = 21x; b = 1

On using, the above formula, we get,

(21 x-1)^{2}=0(21x−1)

2

=0

On solving, we get,

21 x-1=0; \ \ 21 x-1=021x−1=0; 21x−1=0

\Rightarrow 21 x=1; \ \ 21 x=1⇒21x=1; 21x=1

Thus, the value of x are,

x=\frac{1}{21}, \frac{1}{21}x=

21

1

,

21

1

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