Question

2 years ago a man was 5 times has old as his son 2 years later his age will be 8 more than 3 times has old as son.find their present ages

Answer 1

Let son's age today is x

two years ago son's age will be x-2

two years ago father's age will be 5(x-2)

two years later son's age will be x+2

two years later father's age will be 3x+8+2

now, x-2 + 5(x-2) = x+2 + 3x+8+2

x-2 + 5x - 10 = 4x + 12

6x -12 = 4x +12

2x = 24

x = 12

son's present age is 12

fathers present age is 5(x-2) + 2 = 5 (12-2) +2 = 52