Question

20. A cistern 6 m long and 4 m wide, contains water up to a depth of 1 m 25 cm. The total area of the wet surface is

Answer 1

Hi, Here is your answer

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Explanation:

Area of the wet surface = [2(lb + bh + lh) - lb]

= 2(bh + lh) + lb

= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4]m2

= 49m2

Hope it is helpful....

Answer 2

hey here is your answer ☜☆☞

49m2

with explanation

The wet surface will be: the base 6X4=24 m2 plus 2 walls of 1.25X4 = 10m2 plus two walls of 1.25X6 = 15m2

The wet surface will be: the base 6X4=24 m2 plus 2 walls of 1.25X4 = 10m2 plus two walls of 1.25X6 = 15m2total 24+10+15=49m2

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