Question

20. In the given figure, the value of e2 + ed is


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Answer 1

Answer:

Step-by-step explanation:

In ADB

AB2=AD2+BD2

c2=e2+BD2

c2-e2=BD2..........(1)

InCDB

BC2=DC2+BD2

BC2=d2+BD2

BC2-d2=BD2 ............(2)

Now, In ABC

AC2=AB2+BC2

(e+d)2=c2+BC2

(e+d)2-c2=BC2..........(#)

NOW, from (1) and (2)

c2-e2=BC2-d2

from (#)

c2-e2=(e+d)2-c2-d2

c2-e2=e2+d2+2ed-c2-d2

2c2=2e2+2ed

c2=e2+ed

Hence proved

Answer 2

Answer:

The Answer is C raised to the power 2