Question

20 items of which 8 are non defective are inspected one after the another if these items are chosen at random. What is the probability that the first two items inspected are defective.​

Answer 1

Answer:8/20

Step-by-step explanation:

Answer 2

LET THE DEFECTIVE PIECES BE D AND NON DEFECTIVE PIECES BE N

If first two items are inspected then the outcomes can be one of the following:-

(D,N) (D,D) (N,N) (N,D)

Therefore total no. of outcomes are:-4

No. favourable outcomes:-1

{since there is only one outcome of both defective (D,D)}

Therefore,

p(of getting first two items defective) =

no. of favourable outcomes/total no. of outcomes

=1/4.

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