20 men completes one-third of work in 20days. Find additional numbers of persons required to finish rest of work in 25 days
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Given, M1 = 20
M2 = 20 + x
W1 = 1/3
W2 = 1 - 1/3 =2/3
D1 =20 and D2 = 25
According to the formula, M1D1W2 = M2D2W1
20 x20 x (2/3) =(20 + x) x 25 x (1/3)
20 x 20 x (2/3)= (20 + x) x 25/3
= > 16 x 2 = 20 + x
x = 32 - 20 = 12
hope it helps/
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