Math, asked by karan4590, 1 year ago

20% of dolls produced in a factory was defective 25% of the remaining the damage if 4800 Dolby leftover what was the original number of dolls

Answers

Answered by Anonymous
28

let the total number of dolls produced in factory be x

given 20% of total dolls were defective

⇒ defective dolls = 20x/100 = x/5

⇒ remaining dolls = total dolls - defective dolls

⇒ remaining dolls = x - x/5 = 4x/5

given 25% of the remaining dolls are damaged

damged dolls = (25/100) × 4x/5 = x/5

leftover dolls = remaining dolls - damaged dolls

leftover dolls = 4x/5 - x/5 = 3x/5

given leftover dolls = 4800

⇒ 3x/5 = 4800

⇒ x = 8000

⇒ the original number of dolls produced are 8000


Answered by BorahPanda
15
20% defective
Remaining 80%
out of 80% , 25% is damaged
so 25% of 80%= 20%
so only 60% of dolls are left i.e, 4800
original no. of dolls= 4800*100/60= 8000

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