20% of dolls produced in a factory was defective 25% of the remaining the damage if 4800 Dolby leftover what was the original number of dolls
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Answered by
28
let the total number of dolls produced in factory be x
given 20% of total dolls were defective
⇒ defective dolls = 20x/100 = x/5
⇒ remaining dolls = total dolls - defective dolls
⇒ remaining dolls = x - x/5 = 4x/5
given 25% of the remaining dolls are damaged
damged dolls = (25/100) × 4x/5 = x/5
leftover dolls = remaining dolls - damaged dolls
leftover dolls = 4x/5 - x/5 = 3x/5
given leftover dolls = 4800
⇒ 3x/5 = 4800
⇒ x = 8000
⇒ the original number of dolls produced are 8000
Answered by
15
20% defective
Remaining 80%
out of 80% , 25% is damaged
so 25% of 80%= 20%
so only 60% of dolls are left i.e, 4800
original no. of dolls= 4800*100/60= 8000
Remaining 80%
out of 80% , 25% is damaged
so 25% of 80%= 20%
so only 60% of dolls are left i.e, 4800
original no. of dolls= 4800*100/60= 8000
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