Question

20. The number of consecutive zeros in 2^3*3^4*5^4*7 is
(a) 3
(b) 2
(c) 4
(d) 5​

Answer 1

Answer:

We take the minimum number of 2s and 5s [Logically and theoretically too]. So, the number of zeros in X will be 3. In your question, there are three 2s and four 5s. Since there are only three 2s, there will be only one three consecutive zeros.