Question

20 years ago, a father was 5 times as old as his son. Now he is 10 years older than two times the age of his son. find their present age.

you can only answer the equation also ​

Answer 1

Answer:

Let F be the father's age and S be the son's age.

The first statement can bebtranskatedas F = S + 20.

The second statement is F - 5 = 3(S - 5)

Plugging the first equation into the second

S + 20 - 5 = 3(S - 5)

S + 15 = 3(S - 5)

S + 15 = 3S - 15

S + 30 = 3S

30 = 2S

15 = S

So the son is 15, and the father is 35. 5 years ago, they were 10 and 30.

Answer 2

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