Question

2000j of of work is done sliding a 2 kg block up an incline plane of weight 20m (g=10m/s2) work done of the friction is ?

Answer 1

❀ $\large{ \underline\textbf{Answer - }}$



1/2*m*v^2 = m*g*h

m = mass

v = speed

g = acceleration of gravity

h = height; more exactly, the increase in height

Crossing mass out, it can be simplified to:

1/2*v^2 = g*h, then to

h = (v^2)/(2*g)

Let's say d is the distance. Then,

d = 2*h