Question

200ml decimolar H2SO4 and 300ml decimolar HCl mixture is treated with M/5 NaOH solution. For complete neutralization of the mixture, the volume of NaOH needed is
(1) 400ml (2) 250ml (3) 350ml (4) 100ml

Answer 1

Answer:

3) 350ml

Explanation:

Equivalence of acidic solution= Equivalence of basic solution

N₁V₁n₁+N₂V₂n₂=N₃V₃n₃

n=n-factor

N=normality

V=volume

1,2 and 3 subscript stands for H₂SO₄, HCl and NaOH respectively

(2)(0.2)(0.1)+(0.1)(1)(0.3)=(0.2)(V)(1)

V=0.07/0.3=0.350L=350ml

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Answer 2

Hello Friend..!!

The answer of ur question is..!!

Option.D

Thank you