Question

20l^2m + 30alm factories

we will take 10 common
= (10×2×l×l×m) + ( 10×3×a×l×m)
= 10lm(2×l+3×a)
now
10lm(2l+3a)​

Answer 1

Answer:

= ( 10 × 2 × l × l × m ) + ( 10 × 3 × a × l × m )

= 10 lm ( 2 × l + 3 × a )

= 10 lm ( 2l × 3a )

= 10 lm / 2l ( 3a )

= 5m × 3a

= 15ma