Question

20ml of he is diffused through a hole in 10 sec at a pressure of 2atm, find the volume of CH4 diffused in same time at a pressure of 1 atm​

Answer 1

Answer:

The rate of effusion is directly proportional to the mole fraction and inversely proportional to the square root of molar mass.

r

′

r

=

V

′

V

×

t

t

′

=

X

′

X

×

M

M

′

Here, r,V,t,X and M are the rate of diffusion, volume diffused, time for diffusion, mole fraction and the molar mass for He respectively

and r

′

,V

′

,t

′

,X

′

and M

′

are the rate of diffusion, volume diffused, time for diffusion, mole fraction and the molar mass for methane respectively

X

X

×

5

t

′

=

1

2

×

4

16

t

′

=40sec

Hence, the time required to effuse same volume of methane gas is 40 sec.

Answer 2

Explanation:

this is the answer.I think this helps you.