Question

5\10+4k=1......... I need to get the answer as 1\10
How explain.?


please i need a correct answer..

Answer 1

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Given the value of coefficient of volume expansion of 5×10 −4K −1

As, original density of glycerine

ρ=ρ 0

(1+YΔT)

⇒ρ−ρ0

=ρ 0YΔT

Thus, fractional change in the density of glycerin for a rise of 400C in its temperature.

ρ0ρ−ρ0

=YΔT=5×10 −4×40

200×10 −4

=0.020

Answer 2

Answer:

The value of coefficient of volume expansion of glycerin is 5 × 10 ^ - 4K ^ - 1 The fractional change in the density of glycerin for a rise of 40 ^ ∘C ...

Missing: explain.? ‎please

Top answer · 15 votes

Given the value of coefficient of volume expansion of 5 × 10^- 4K^- 1 As, original density of glycerine lρ = ρ0 ( 1 + YΔT ) ρ - ρ0 = ρ0YΔ ... More