21 + 1.
EXERCISE 2.3
1. Find the remainder when r' + 3x2 + 3x + 1 is divided by
1
(v) 5+ 27
(i) x + 1
(iv) xtt
(ii) x -
2
2. Find the remainder when xy - ar? + 6x -a is divided by .x - a.
3. Check whether 7 + 3x is a factor of 3x + 7x
Answers
Answer:
72
Rohit18Bhadauria
Genius
1.1K answers
41.6K people helped
Given:
Polynomial p(x)=x⁴-2x³+3x²-ax+3a-7 which gives remainder 19 when divided by x+1
To Find:
Value of 'a'.
Value of remainder when p(x) is divided by x+2
Solution:
Dividend= x⁴-2x³+3x²-ax+3a-7
Divisor= x+1
Remainder= 19
On dividing x⁴-2x³+3x²-ax+3a-7 by x+1, we get
(Calculation in First attachment)
Remainder= 4a-1
Also, it is given that
Remainder=19
⇒ 4a-1= 19
⇒ 4a= 20
⇒ a= 5
Now, after putting value of a in dividend, we get
Dividend= x⁴-2x³+3x²-(5)x+3(5)-7
Dividend= x⁴-2x³+3x²-5x+15-7
Dividend= x⁴-2x³+3x²-5x+8
Now,
Dividend= x⁴-2x³+3x²-5x+8
Divisor= x+2
After dividing x⁴-2x³+3x²-5x+8 by x+2, we get
(Calculation in second attachment)
Remainder= 62
Hence, the value of a is 5 and required remainder is 62
72
Rohit18Bhadauria
Genius
1.1K answers
41.6K people helped
Given:
Polynomial p(x)=x⁴-2x³+3x²-ax+3a-7 which gives remainder 19 when divided by x+1
To Find:
Value of 'a'.
Value of remainder when p(x) is divided by x+2
Solution:
Dividend= x⁴-2x³+3x²-ax+3a-7
Divisor= x+1
Remainder= 19
On dividing x⁴-2x³+3x²-ax+3a-7 by x+1, we get
(Calculation in First attachment)
Remainder= 4a-1
Also, it is given that
Remainder=19
⇒ 4a-1= 19
⇒ 4a= 20
⇒ a= 5
Now, after putting value of a in dividend, we get
Dividend= x⁴-2x³+3x²-(5)x+3(5)-7
Dividend= x⁴-2x³+3x²-5x+15-7
Dividend= x⁴-2x³+3x²-5x+8
Now,
Dividend= x⁴-2x³+3x²-5x+8
Divisor= x+2
After dividing x⁴-2x³+3x²-5x+8 by x+2, we get
(Calculation in second attachment)
Remainder= 62
Hence, the value of a is 5 and required remainder is 62