Question

(2¹+3¹+4¹)⁰ by using laws
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Answer 1

ᴀɴsᴡᴇʀ:-

✥Formula used:

${a}^{0} = 1$

✥Solution:

$( {2}^{1} + {3}^1 + {4}^1)^0$

$➺2 ^{1 \times 0} + {3}^{1 \times 0} + {4}^{1 \times 0}$

$➺ {2}^{0} + {3}^{0} + {4}^{0}$

$➺1 + 1 + 1 \\ \\ ➺3$

Therefore, The answer is 3.

Answer 2

ᴀɴsᴡᴇʀ:-

✥Formula used:

${a}^{0} = 1$

✥Solution:

$( {2}^{1} + {3}^1 + {4}^1)^0$

$➺2 ^{1 \times 0} + {3}^{1 \times 0} + {4}^{1 \times 0}$

$➺ {2}^{0} + {3}^{0} + {4}^{0}$

$➺1 + 1 + 1 \\ \\ ➺3$

Therefore, The answer is 3.