A CONVEX LENS HAS FOCAL LENGTH OF 10 CM. AT WHAT DISTANCE LENS SHOULD BE PLACED SO IT FORMS REAL AND INVERTED IMAGE?IF OBJECT IS 20 CM AWAY FROM LENS. WHAT IS SIZE OF IMAGE IF LENS IS 2 M HIGH? DRAW RAY DIAGRAM
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•Focal length=10cm
•Image distance=20cm
Using sign convention,
F is positive and v is also positive
Therefore, Lens formula,
1/F=1/v-1/u
1/10=1/20–1/u
1/u=1/20–1/10
1/u=(10–20)/200
1/u=-10/200
u=-20
Object distance=20cm(minus indicates that the lens is converging lens)
H1=height of image and H2=height of object
H1/H2=-v/u
H1/2=-20/20
H1=2cm
Therefore, height of image is 2cm.
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