Question

1.
Find the area of a triangle when two sides are 24cm and 10 cm and the perimeter
of the triangle is 62 cm.​

Answer 1

Answer:

116.92cm

Step-by-step explanation:

Answer 2

Answer:

21√31

Step-by-step explanation:

Perimeter of triangle=62

consider the remaining side as x

so, 24+10+X= 62

34+X=62

x= 62-34=28

now for area $\sqrt{s(s-a)(s-b)(s-c)}$

s=a+b+c/2

s=31

now$\sqrt{31(31-10)(31-24)(31-28)}$

=21√31