2145 into binary numbers
Answers
Answered by
9
Heya user
Here is your answer !!
_____________________
The binary form of 2145 is
= 100001100001 .
_____________________
NOTE : see the attachment for the process .
Hope it helps !!
Here is your answer !!
_____________________
The binary form of 2145 is
= 100001100001 .
_____________________
NOTE : see the attachment for the process .
Hope it helps !!
Attachments:
![](https://hi-static.z-dn.net/files/dc3/00bcc5650a34034cc1cd16df317202f8.jpg)
Incredible29:
pl follow if u lyk my answer
Answered by
11
Procedure:
(1) Divide the number by 2 and note down the remainder.
(2) Note down the remainders obtained from the bottom, which gives the binary system for the given number.
Solution:
Here I am writing Quotient as Q and Remainder as R, as it is difficult to write always.
Now,
2145/2 = 1072(Q) = 1(R)
1072/2 = 536(Q) = 0(R)
536/2 = 268(Q) = 0(R)
268/2 = 134(Q) = 0(R)
134/2 = 67(Q) = 0(R)
67/2 = 33(Q) = 1(R)
33/2 = 16(Q) = 1(R)
16/2 = 8(Q) = 0(R)
8/2 = 4(Q) = 0(R)
4/2 = 2(Q) = 0(R)
2/2 = 1(Q) = 0(R)
1/2 = 0(Q) = 1(R)
Therefore the binary notation is (100001100001).
Hope this helps!
(1) Divide the number by 2 and note down the remainder.
(2) Note down the remainders obtained from the bottom, which gives the binary system for the given number.
Solution:
Here I am writing Quotient as Q and Remainder as R, as it is difficult to write always.
Now,
2145/2 = 1072(Q) = 1(R)
1072/2 = 536(Q) = 0(R)
536/2 = 268(Q) = 0(R)
268/2 = 134(Q) = 0(R)
134/2 = 67(Q) = 0(R)
67/2 = 33(Q) = 1(R)
33/2 = 16(Q) = 1(R)
16/2 = 8(Q) = 0(R)
8/2 = 4(Q) = 0(R)
4/2 = 2(Q) = 0(R)
2/2 = 1(Q) = 0(R)
1/2 = 0(Q) = 1(R)
Therefore the binary notation is (100001100001).
Hope this helps!
Similar questions
Hindi,
9 months ago
Computer Science,
9 months ago
Science,
9 months ago
Geography,
1 year ago
Political Science,
1 year ago
Physics,
1 year ago