Question

22. Equation of (x+1)2-x2=0 has number of real roots equal to: (a)1 (b)2 (c)3 (d)4​

Answer 1

Answer:

1

Step-by-step explanation:

2x+1=0

x=-1/2

hope u understand

Answer 2

Answer:

CORRECT ANS. IS (C)

Step-by-step explanation:

Given equation is (x2+1)2−x2=0

⇒(x2)2+(1)2+2(x)2(1)−x2=0

⇒(x2)2+x2+1=0

Let x2=y

⇒y2+1y+1=0

Now, D=b2−4ac

⇒D=(1)2−4(1)(1)=1−4

⇒D=−3

⇒D<0

So, the given equation y2+y+1=0 has no real roots.

∴ the equation $$\left ( x^{2} + 1 \right )^{2} - x^{2} =0$ has no real roots.

Hence, the correct answer is option [C].